A spherical liquid drop has radius 1 mm and surface tension 0.075 N/m. If the excess pressure inside the drop is N Pa, find N.

Question

G1 Physics · Accepted Answer

For a liquid drop, ΔP = 2S/R. Substitute S = 0.075 N/m, R = 1 mm = 10⁻³ m. Therefore, ΔP = 2×0.075/10⁻³ = 150 Pa. Hence, N = 150.