A uniform string of length 1.2 m is fixed at both ends. The transverse wave speed on the string is 120 m/s. If its fundamental frequency is N Hz, find N.

Question

G1 Physics · Accepted Answer

For a string fixed at both ends, f₁ = v/(2L). Substitute v = 120 m/s, L = 1.2 m. Thus, f₁ = 120/[2(1.2)] = 120/2.4 = 50 Hz. Hence, N = 50.