A uniform string of length 1.2 m is fixed at both ends and has transverse wave speed 120 m/s. If it vibrates in its fifth harmonic, the frequency is N Hz. Find N.
Physics · Wave Motion · stationary wave of string and sonometer
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Question

A uniform string of length 1.2 m is fixed at both ends and has transverse wave speed 120 m/s. If it vibrates in its fifth harmonic, the frequency is N Hz. Find N.

G1 Physics · Accepted Answer

The fundamental frequency is f₁ = v/(2L) = 120/[2(1.2)] = 50 Hz. For the fifth harmonic, f₅ = 5f₁ = 5×50 = 250 Hz. Hence, N = 250.