A string of length 0.60 m is fixed at one end and perfectly free at the other. The transverse wave speed is 120 m/s. If its fundamental frequency is N Hz, find N.
Physics · Wave Motion · stationary wave of string and sonometer
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Question

A string of length 0.60 m is fixed at one end and perfectly free at the other. The transverse wave speed is 120 m/s. If its fundamental frequency is N Hz, find N.

G1 Physics · Accepted Answer

For a fixed-free string, L = λ₁/4. Therefore, f₁ = v/(4L). Substitute v = 120 m/s, L = 0.60 m. Thus, f₁ = 120/[4(0.60)] = 120/2.4 = 50 Hz. Hence, N = 50.