A fixed-free string has fundamental frequency 50 Hz. If its third allowed resonance frequency is N Hz, find N.

Question

G1 Physics · Accepted Answer

For a fixed-free string, the allowed frequencies are f₁, 3f₁, 5f₁, 7f₁, ... The third allowed resonance is 5f₁. Therefore, f = 5×50 = 250 Hz. Hence, N = 250.