A uniform organ pipe is closed at one end and open at the other. Which expression gives its allowed resonance frequencies?
Options

Question

A uniform organ pipe is closed at one end and open at the other. Which expression gives its allowed resonance frequencies?

G1 Physics · Accepted Answer

The closed end is a displacement node and the open end is a displacement antinode. Thus, Lₑ = (2n−1)λₙ/4. Therefore, λₙ = 4Lₑ/(2n−1), and fₙ = (2n−1)v/(4Lₑ). Only odd multiples of the fundamental are present. Correct option: B.