A pipe closed at one end has geometrical length 0.84 m. The end correction at its single open end is 1 cm. If the speed of sound is 340 m/s and the fundamental frequency is N Hz, find N.
Physics · Wave Motion · organ pipe and resonance tube
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Question

A pipe closed at one end has geometrical length 0.84 m. The end correction at its single open end is 1 cm. If the speed of sound is 340 m/s and the fundamental frequency is N Hz, find N.

G1 Physics · Accepted Answer

For a pipe closed at one end, there is one open end. Therefore, Lₑ = L+e. Substitute: Lₑ = 0.84+0.01 = 0.85 m. For the fundamental mode, f₁ = v/(4Lₑ). Hence, f₁ = 340/[4(0.85)] = 340/3.4 = 100 Hz. Therefore, N = 100.