Two immiscible liquids of refractive indices 8/5 and 3/2 respectively are put in a beaker as shown in the figure. The height of each column is 6 cm. A coin is placed at the bottom of the beaker. For near normal vision, the apparent depth of the coin is α/4 cm. The value of α i $s______.$

Question

G1 Physics · Accepted Answer

For near-normal viewing through two liquid layers, hₐₚₚ = h₁/μ₁ + h₂/μ₂ = 6/(3/2) + 6/(8/5) = 4 + 15/4 = 31/4 cm Given apparent depth = α/4 cm, α = 31.

Two immiscible liquids of refractive indices 8/5 and 3/2 respectively are put in a beaker as shown in the figure. The height of each column is 6 cm. A coin is placed at the bottom of the beaker. For near normal vision, the apparent depth of the coin is α/4 cm. The value of α i s______.