The deflection in moving coil galvanometer falls from 25 divisions to 5 division when a shunt of 24 Ω is applied. The resistance of galvanometer coil will be :
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The deflection in moving coil galvanometer falls from 25 divisions to 5 division when a shunt of 24 Ω is applied. The resistance of galvanometer coil will be :

G1 Physics · Accepted Answer

Let x be the current per division. Before applying shunt: I(g) = 25x After applying shunt: Current through galvanometer = 5x Current through shunt = 20x Potential difference across galvanometer and shunt is same: 5xG = 20x × 24 Therefore, G = 4 × 24 = 96 Ω