A cylinder is rolling down on an inclined plane of inclination 60°. It's acceleration during rolling down will be x/√3 m/s², where x = _________. (use g = 10 m/s²).
Physics · Rotational Motion · rolling on inclined surface
JEE Mains 2024 29 Jan Morning Shift

Question

A cylinder is rolling down on an inclined plane of inclination 60°. It's acceleration during rolling down will be x/√3 m/s², where x = _________. (use g = 10 m/s²).

G1 Physics · Accepted Answer

For pure rolling, a(cm) = g sinθ / [1 + I/(MR²)] For a solid cylinder, I = ½MR² Therefore, a(cm) = g sin60° /(1 + 1/2) = 10 × (√3/2) × (2/3) = 10/√3 m/s² Comparing with x/√3 m/s², x = 10