A spherical body of mass 100 g is dropped from a height of 10 m from the ground. After hitting the ground, the body rebounds to a height of 5m. The impulse of force imparted by the ground to the body is given by : (given g = 9.8 m/s²)
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Question

A spherical body of mass 100 g is dropped from a height of 10 m from the ground. After hitting the ground, the body rebounds to a height of 5m. The impulse of force imparted by the ground to the body is given by : (given g = 9.8 m/s²)

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G1 Physics · Accepted Answer

Impulse, I = ΔP = P(final) - P(initial) Mass, m = 100 g = 0.1 kg Speed just before hitting ground: v(initial) = √(2gh₁) = √(2 × 9.8 × 10) = 14 m/s Speed just after rebound: v(final) = √(2gh₂) = √(2 × 9.8 × 5) = 7√2 m/s Taking upward as positive: I = 0.1[7√2 - (-14)] = 0.1(14 + 7√2) ≈ 2.39 kg ms⁻¹