Two cells are connected in opposition as shown. Cell E₁ is of 8 V emf and 2 Ω internal resistance; the cell E₂ is of 2 V emf and 4 Ω internal resistance. The terminal potential difference of cell E₂ is:

Question

G1 Physics · Accepted Answer

Image The cells are in opposition. Current: I = (8 - 2)/(2 + 4) = 6/6 = 1 A Applying Kirchhoff from C to B: V(C) - 2 - 4(1) = V(B) Therefore, V(C) - V(B) = 6 V Hence, the terminal potential difference of cell E₂ is 6 V.