If mass is written as m = kcᴾG⁻¹ᐟ²h¹ᐟ² then the value of P will be : (Constants have their usual meaning with k a dimensionless constant)
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If mass is written as m = kcᴾG⁻¹ᐟ²h¹ᐟ² then the value of P will be : (Constants have their usual meaning with k a dimensionless constant)

G1 Physics · Accepted Answer

Given: m = kcᴾG⁻¹ᐟ²h¹ᐟ² Dimensions: [m] = M [c] = LT⁻¹ [G] = M⁻¹L³T⁻² [h] = ML²T⁻¹ Therefore, M = (LT⁻¹)ᴾ × (M⁻¹L³T⁻²)⁻¹ᐟ² × (ML²T⁻¹)¹ᐟ² Comparing the power of L: 0 = P - 3/2 + 1 P = 1/2