A parallel plate capacitor has capacitance C = 200 pF. It is connected to a 230 V AC supply with angular frequency 300 rad s⁻¹. The rms values of conduction current in the circuit and displacement current in the capacitor respectively are:
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Question

A parallel plate capacitor has capacitance C = 200 pF. It is connected to a 230 V AC supply with angular frequency 300 rad s⁻¹. The rms values of conduction current in the circuit and displacement current in the capacitor respectively are:

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G1 Physics · Accepted Answer

For a capacitor: X꜀ = 1/(ωC) Therefore, I = V/X꜀ = VωC = 230 × 300 × 200 × 10⁻¹² = 13.8 μA The displacement current between the plates is equal to the conduction current in the connecting wires. Hence, Conduction current = 13.8 μA Displacement current = 13.8 μA