A simple pendulum of length 1 m has a wooden bob of mass 1 kg. It is struck by a bullet of mass 10⁻² kg moving with a speed of 2 × 10² m s⁻¹. The bullet gets embedded into the bob. The height to which the bob rises before swinging back is: [Use g = 10 m s⁻²]
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Question

A simple pendulum of length 1 m has a wooden bob of mass 1 kg. It is struck by a bullet of mass 10⁻² kg moving with a speed of 2 × 10² m s⁻¹. The bullet gets embedded into the bob. The height to which the bob rises before swinging back is: [Use g = 10 m s⁻²]

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G1 Physics · Accepted Answer

During collision, momentum is conserved: μ \mu μ = (M + m)V 10⁻² × 2 × 10² ≈ 1 × V V ≈ 2 m s⁻¹ After collision, kinetic energy converts to gravitational potential energy: h = V²/(2g) = 4/20 = 0.20 m