A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm. The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from the slit, will be:
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Question

A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm. The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from the slit, will be:

G1 Physics · Accepted Answer

For first minimum: a sinθ = λ sinθ = λ/a = 2/4 = 1/2 θ = 30° The central maximum extends from -30° to +30°. Therefore, angular spread = 60°