If the root mean square velocity of hydrogen molecule at a given temperature and pressure is 2 km/s, the root mean square velocity of oxygen at the same condition in km/s is:
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If the root mean square velocity of hydrogen molecule at a given temperature and pressure is 2 km/s, the root mean square velocity of oxygen at the same condition in km/s is:

G1 Physics · Accepted Answer

For a gas: v(rms) = √(3RT/M) At the same temperature: v₁/v₂ = √(M₂/M₁) For hydrogen and oxygen: 2/v₂ = √(32/2) = 4 Therefore, v₂ = 0.5 km/s