The co-ordinates of a particle moving in x-y plane are given by:
x = 2 + 4t, y = 3t + 8t².
The motion of the particle is:

Question

The co-ordinates of a particle moving in x-y plane are given by: x = 2 + 4t, y = 3t + 8t². The motion of the particle is:

G1 Physics · Accepted Answer

For x-coordinate: x = 2 + 4t vₓ = dx/dt = 4 aₓ = 0 For y-coordinate: y = 3t + 8t² vᵧ = dy/dt = 3 + 16t aᵧ = 16 Thus acceleration is constant. For the path: t = (x - 2)/4 Substituting into y: y = 3[(x - 2)/4] + 8[(x - 2)/4]² This is a quadratic relation between y and x. Therefore, the path is parabolic and the motion is uniformly accelerated.