A body of m kg slides from rest along the curve of vertical circle from point A to B in friction less path. The velocity of the body at B is:
(given, R = 14 m, g = 10 m/s² and √2 = 1.4)

Question

A body of m kg slides from rest along the curve of vertical circle from point A to B in friction less path. The velocity of the body at B is: (given, R = 14 m, g = 10 m/s² and √2 = 1.4)

G1 Physics · Accepted Answer

Image Apply work-energy theorem from A to B. The vertical drop is: Δh = R + R/√2 Therefore: mgΔh = ½mv(B)² v(B)² = 2gR(1 + 1/√2) Using: R = 14 m g = 10 m/s² √2 = 1.4 v(B) ≈ 21.9 m/s