Given below are two statements:
Statement-I: Figure shows the variation of stopping potential with frequency (ν) for the two photosensitive materials M₁ and M₂. The slope gives value of h/e, where h is Planck's constant, e is the charge of electron.
Statement-II: M₂ will emit photoelectrons of greater kinetic energy for the incident radiation having same frequency.
In the light of the above statements, choose the most appropriate answer from the options given below.

Question

Given below are two statements:

Statement-I: Figure shows the variation of stopping potential with frequency (ν) for the two photosensitive materials M₁ and M₂. The slope gives value of h/e, where h is Planck's constant, e is the charge of electron.

Statement-II: M₂ will emit photoelectrons of greater kinetic energy for the incident radiation having same frequency.

In the light of the above statements, choose the most appropriate answer from the options given below.

G1 Physics · Accepted Answer

Image Einstein photoelectric equation: eV₀ = hν - ϕ Therefore: V₀ = (h/e)ν - ϕ/e Hence the slope of V₀ versus ν graph is h/e. So Statement-I is correct. From the graph, M₂ has a higher threshold frequency and hence a higher work function. For the same incident frequency: K(max) = hν - ϕ Therefore M₂ gives smaller, not greater, maximum kinetic energy. So Statement-II is incorrect.