Two conducting circular loops A and B are placed in the same plane with their centres coinciding as shown in figure. The mutual inductance between them is:

Question

G1 Physics · Accepted Answer

Image Since b >> a, magnetic field produced by the larger loop B is nearly uniform over the smaller loop A. Magnetic field at the centre of loop B: B = μ₀I/(2b) Flux through loop A: Φ = B × πa² = [μ₀I/(2b)]πa² Using: Φ = MI Therefore: M = μ₀πa²/(2b)