Match list-I with list-II:
List-I
(A) Kinetic energy of planet
(B) Gravitation Potential energy of Sun-planet system.
(C) Total mechanical energy of planet
(D) Escape energy at the surface of planet for unit mass object
List-II (I) -GMm/a (II) GMm/(2a) (III) Gm/r (IV) -GMm/(2a)
(Where a = radius of planet orbit, r = radius of planet, M = mass of Sun, m = mass of planet)
Choose the correct answer from the options given below:

Question

Match list-I with list-II:

List-I
(A) Kinetic energy of planet
(B) Gravitation Potential energy of Sun-planet system.
(C) Total mechanical energy of planet
(D) Escape energy at the surface of planet for unit mass object

List-II (I) -GMm/a (II) GMm/(2a) (III) Gm/r (IV) -GMm/(2a)

(Where a = radius of planet orbit, r = radius of planet, M = mass of Sun, m = mass of planet)

Choose the correct answer from the options given below:

G1 Physics · Accepted Answer

For a planet in a circular orbit: Kinetic energy: K = GMm/(2a) → II Potential energy: U = -GMm/a → I Total mechanical energy: E = -GMm/(2a) → IV Escape energy per unit mass from the surface of a planet: E(escape) = Gm/r → III Therefore: A-II, B-I, C-IV, D-III