The ratio of the shortest wavelength of Balmer series to the shortest wavelength of Lyman series for hydrogen atom is :
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The ratio of the shortest wavelength of Balmer series to the shortest wavelength of Lyman series for hydrogen atom is :

G1 Physics · Accepted Answer

For the shortest wavelength, the upper level is n = ∞. Rydberg formula: 1/λ = R(1/n₁² - 1/n₂²) For Lyman series: n₁ = 1, n₂ = ∞ 1/λ(L) = R For Balmer series: n₁ = 2, n₂ = ∞ 1/λ(B) = R/4 Therefore: λ(B)/λ(L) = 4 Hence: λ(B) : λ(L) = 4 : 1