Electromagnetic waves travel in a medium with speed of 1.5 × 10⁸ m s⁻¹. The relative permeability of the medium is 2.0. The relative permittivity will be :
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Electromagnetic waves travel in a medium with speed of 1.5 × 10⁸ m s⁻¹. The relative permeability of the medium is 2.0. The relative permittivity will be :

G1 Physics · Accepted Answer

For an electromagnetic wave in a medium: v = c/√(εᵣμᵣ) Therefore: εᵣμᵣ = (c/v)² = [3 × 10⁸/(1.5 × 10⁸)]² = 4 Given: μᵣ = 2 Hence: εᵣ = 4/2 = 2