A total of 48 J heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by 2°C. The work done by the gas is : (Given, R = 8.3 J K⁻¹ mol⁻¹.)
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A total of 48 J heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by 2°C. The work done by the gas is : (Given, R = 8.3 J K⁻¹ mol⁻¹.)

G1 Physics · Accepted Answer

First law of thermodynamics: ΔQ = ΔU + W For one mole of helium: Cᵥ = 3R/2 Therefore: 48 = (1)(3R/2)(2) + W 48 = 3R + W W = 48 - 3(8.3) = 23.1 J