In the given electromagnetic wave Eᵧ = 600 sin(ωt - kx) V m⁻¹, intensity of the associated light beam is (in W/m²); (Given ε₀ = 9 × 10⁻¹² C² N⁻¹ m⁻²)
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In the given electromagnetic wave Eᵧ = 600 sin(ωt - kx) V m⁻¹, intensity of the associated light beam is (in W/m²); (Given ε₀ = 9 × 10⁻¹² C² N⁻¹ m⁻²)

G1 Physics · Accepted Answer

Average intensity of an electromagnetic wave: I = ½ ε₀ c E₀² Here: E₀ = 600 V/m Therefore: I = ½ × 9 × 10⁻¹² × 3 × 10⁸ × 600² = 486 W/m²