Two open organ pipes of length 60 cm and 90 cm resonate at 6th and 5th harmonics respectively. The difference of frequencies for the given modes i s _____ Hz. (Velocity of sound in air = 333 m/s)

Question

G1 Physics · Accepted Answer

For an open organ pipe: fₙ = nv/(2L) For the 60 cm pipe at 6th harmonic: f₁ = 6 × 333/[2 × 0.60] For the 90 cm pipe at 5th harmonic: f₂ = 5 × 333/[2 × 0.90] Difference: Δf = f₁ - f₂ = 740 Hz