Three bodies A, B and C have equal kinetic energies and their masses are 400 g, 1.2 kg and 1.6 kg respectively. The ratio of their linear momenta is :
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Question

Three bodies A, B and C have equal kinetic energies and their masses are 400 g, 1.2 kg and 1.6 kg respectively. The ratio of their linear momenta is :

G1 Physics · Accepted Answer

For equal kinetic energies: K = p²/(2m) Therefore: p = √(2mK) Since K is the same for all three bodies: p ∝ √m Hence: p(A) : p(B) : p(C) = √400 : √1200 : √1600 = 20 : 20√3 : 40 = 1 : √3 : 2