An alternating emf E = 110√2 sin(100t) volt is applied to a capacitor of 2 μF, the rms value of current in the circuit i s ______ mA.

Question

G1 Physics · Accepted Answer

Given: E = 110√2 sin(100t) Therefore: V(rms) = 110 V Angular frequency: ω = 100 rad/s Capacitance: C = 2 μF = 2 × 10⁻⁶ F Capacitive reactance: X(C) = 1/(ωC) = 1/[100 × 2 × 10⁻⁶] = 5000 Ω Hence: I(rms) = V(rms)/X(C) = 110/5000 A = 0.022 A = 22 mA