A particle moving in a straight line covers half the distance with speed 6 m/s. The other half is covered in two equal time intervals with speeds 9 m/s and 15 m/s respectively. The average speed of the particle during the motion is:
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Question

A particle moving in a straight line covers half the distance with speed 6 m/s. The other half is covered in two equal time intervals with speeds 9 m/s and 15 m/s respectively. The average speed of the particle during the motion is:

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G1 Physics · Accepted Answer

Let each half of the total distance be S. For the second half, the two equal time intervals are t and t. Therefore: S = 9t + 15t = 24t For the first half: S = 6t₁ Hence: 6t₁ = 24t t₁ = 4t Total distance: = 2S = 48t Total time: = t₁ + 2t = 4t + 2t = 6t Average speed: v(avg) = 48t/6t = 8 m/s