A square loop of side 15 cm being moved towards right at a constant speed of 2 cm/s as shown in figure. The front edge enters the 50 cm wide magnetic field at t = 0. The value of induced emf in the loop at t = 10 s will be :

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G1 Physics · Accepted Answer

Image In 10 s, the loop moves: x = vt = 2 cm/s × 10 s = 20 cm The loop side is 15 cm, so at t = 10 s the complete loop is inside the uniform magnetic field. Hence magnetic flux through the loop is constant. Therefore: ε = -dΦ/dt = 0