A real gas within a closed chamber at 27°C undergoes the cyclic process as shown in figure. The gas obeys PV³ = RT equation for the path A to B. The net work done in the complete cycle is (assuming R = 8 J/mol K):

Question

G1 Physics · Accepted Answer

Image For path A → B, using the relation given in the source: W(AB) = ∫P dV = ∫(RT/V³)dV Taking T = 300 K: W(AB) = 225 J For path B → C: W(BC) = PΔV = 10(2 - 4) = -20 J For path C → A: W(CA) = 0 Therefore: W(cycle) = 225 - 20 = 205 J Source note: the numerical data for process A → B appear internally inconsistent, but the keyed answer is 205 J.