A capacitor of reactance 4√3 Ω and a resistor of resistance 4 Ω are connected in series with an ac source of peak value 8√2 V. The power dissipation in the circuit i s ______ W.

Question

G1 Physics · Accepted Answer

Given: X(C) = 4√3 Ω R = 4 Ω Impedance: Z = √[R² + X(C)²] = √[4² + (4√3)²] = √(16 + 48) = 8 Ω Peak voltage: V₀ = 8√2 V Therefore: V(rms) = V₀/√2 = 8 V Current: I(rms) = V(rms)/Z = 8/8 = 1 A Power dissipated: P = I(rms)²R = 1² × 4 = 4 W