A 10 wire potentiometer has first five wires of cross sectional radius r and next five wires of radius 2r. The wires are uniform and made of same material. An ideal cell of emf 2 V is connected across the potentiometer wire. What length of the potentiometer wire will balance the emf of—
Select all that apply

Question

A 10 wire potentiometer has first five wires of cross sectional radius r and next five wires of radius 2r. The wires are uniform and made of same material. An ideal cell of emf 2 V is connected across the potentiometer wire. What length of the potentiometer wire will balance the emf of—

Select all that apply

G1 Physics · Accepted Answer

Resistance per unit length of first five wires is four times that of next five. Total resistance ∝ 5×4 + 5×1 = 25 units. Potential drop per 100 cm is 2×4/25 = 0.32 V in each thin wire and 2×1/25 = 0.08 V in each thick wire. Thus 1.0 V balances at 312.5 cm, 1.5 V at 468.75 cm, and 1.8 V at 750 cm. None of the listed numeric options matches; retain source statement and replace options before platform upload if exact-key enforcement is required.