A particle moving with constant acceleration covers 24 m during the 4th second and 36 m during the 7th second. The distance covered during the 10th second is:
Options

Question

A particle moving with constant acceleration covers 24 m during the 4th second and 36 m during the 7th second. The distance covered during the 10th second is:

G1 Physics · Accepted Answer

For constant acceleration, displacement in the nth second is sₙ = u + (a/2)(2n − 1). Thus 24 = u + 7a/2 and 36 = u + 13a/2. Subtracting gives 12 = 3a, so a = 4 m s⁻². The difference between the 10th- and 7th-second displacements is 3a = 12 m. Therefore s₁₀ = 36 + 12 = 48 m.