A particle moving with constant acceleration has velocity 6 m s⁻¹ at t = 2 s and 18 m s⁻¹ at t = 5 s. Its displacement from t = 2 s to t = 7 s is:
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A particle moving with constant acceleration has velocity 6 m s⁻¹ at t = 2 s and 18 m s⁻¹ at t = 5 s. Its displacement from t = 2 s to t = 7 s is:

G1 Physics · Accepted Answer

Acceleration a = (18 − 6)/(5 − 2) = 4 m s⁻². From t = 2 s to t = 7 s, Δt = 5 s and initial velocity for this interval is 6 m s⁻¹. Hence s = 6(5) + (1/2)(4)(25) = 30 + 50 = 80 m.