A particle starts with velocity 4 m s⁻¹ and constant acceleration 2 m s⁻². The ratio of distances covered in the 5th and 3rd seconds is:
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A particle starts with velocity 4 m s⁻¹ and constant acceleration 2 m s⁻². The ratio of distances covered in the 5th and 3rd seconds is:

G1 Physics · Accepted Answer

sₙ = u + (a/2)(2n − 1). Thus s₅ = 4 + 1×9 = 13 m and s₃ = 4 + 1×5 = 9 m. Ratio = 13:9.