A vehicle accelerates uniformly from 10 m s⁻¹ to 30 m s⁻¹ over 200 m. The time taken is:
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A vehicle accelerates uniformly from 10 m s⁻¹ to 30 m s⁻¹ over 200 m. The time taken is:

G1 Physics · Accepted Answer

For constant acceleration, average velocity = (u + v)/2 = 20 m s⁻¹. Hence t = s/v_avg = 200/20 = 10 s.