A ball thrown vertically upward returns to the point of projection after 6 s. Taking g = 10 m s⁻², the distance travelled by the ball in the 4th second is:
Options

Question

A ball thrown vertically upward returns to the point of projection after 6 s. Taking g = 10 m s⁻², the distance travelled by the ball in the 4th second is:

G1 Physics · Accepted Answer

Total time of flight = 2u/g = 6, so u = 30 m s⁻¹. The ball reaches the top at 3 s. The 4th second is the first second of downward fall from rest, so it covers 5 m.