Two identical particles, each of mass m, move in a circle of radius a about their common centre under mutual gravitational attraction. Their angular speed is:
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Question

Two identical particles, each of mass m, move in a circle of radius a about their common centre under mutual gravitational attraction. Their angular speed is:

G1 Physics · Accepted Answer

The separation between the particles is 2a. Gravitational force: F = Gm²/(2a)² = Gm²/(4a²) This provides centripetal force for each particle: mω²a = Gm²/(4a²) Therefore: ω² = Gm/(4a³) ω = √(Gm/4a³) Hence option B.