The fundamental frequency of a string fixed at both ends is 50 Hz. Its mass is 18 g and linear mass density is 20 g m⁻¹. Find the transverse-wave speed in m s⁻¹.

Question

G1 Physics · Accepted Answer

String length: L = m/μ = 18 g / (20 g m⁻¹) = 0.9 m For the fundamental mode of a string fixed at both ends: f = v/(2L) Therefore: v = 2Lf = 2 × 0.9 × 50 = 90 m s⁻¹ Final answer: 90.