A particle moves according to x(t)=t²−8t+12 m. Find the time interval, in seconds, between its two crossings of the origin.

Question

G1 Physics · Accepted Answer

At the origin x=0: t²−8t+12=(t−2)(t−6)=0. The crossings occur at 2 s and 6 s, so the interval is 4 s.