Four numbers are in AP. Their sum is 40 and the difference between the largest and smallest is 12. Find the largest number.
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Four numbers are in AP. Their sum is 40 and the difference between the largest and smallest is 12. Find the largest number.

G1 Physics · Accepted Answer

Let the four terms be a−3d,a−d,a+d,a+3d. Their sum is 4a=40, so a=10. Largest−smallest=6d=12, so d=2. Largest=10+6=16.