Find the distance between the parallel lines 3x + 4y − 5 = 0 and 3x + 4y + 15 = 0.

Question

G1 Physics · Accepted Answer

For Ax+By+C₁=0 and Ax+By+C₂=0, distance=|C₂−C₁|/√(A²+B²)=|15−(−5)|/5=20/5=4.