The trajectory of a projectile is y = x − x²/20, where x and y are in metres. Find its horizontal range, in metres.

Question

G1 Physics · Accepted Answer

At ground level y=0: x−x²/20=0 ⇒ x(1−x/20)=0. The two ground points are x=0 and x=20, so the horizontal range is 20 m.