Find the area enclosed between y = x² and y = 2x.

Question

G1 Physics · Accepted Answer

Intersection points are given by x²=2x: x(x−2)=0, so x=0,2. Between 0 and 2, 2x lies above x². Area = ∫₀²(2x−x²)dx = [x²−x³/3]₀² = 4−8/3 = 4/3 square units.