Find the area enclosed between y = x and y = x² in the interval 0 ≤ x ≤ 1.

Question

G1 Physics · Accepted Answer

For 0≤x≤1, x≥x². Area = ∫₀¹(x−x²)dx = [x²/2−x³/3]₀¹ = 1/2−1/3 = 1/6 square units.