Find the area enclosed between y = x² and y = 4 − x².

Question

G1 Physics · Accepted Answer

Intersection points satisfy x²=4−x²: 2x²=4 → x=±√2. Area = ∫₋√2→√2(4−2x²)dx. Using symmetry: Area = 2[4x−2x³/3]₀→√2 = 2[4√2−4√2/3] = 16√2/3 square units.