Find the area enclosed between y = x + 2 and y = x².

Question

G1 Physics · Accepted Answer

Intersections satisfy x²=x+2: (x−2)(x+1)=0, so x=−1,2. The line is above the parabola between these points. Area = ∫₋₁²(x+2−x²)dx = [x²/2+2x−x³/3]₋₁² = 9/2 square units.