The voltage and current across an AC load are v = 100√2 sinωt V and i = 5√2 sin(ωt - 60°) A. Find the average power absorbed by the load.
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The voltage and current across an AC load are v = 100√2 sinωt V and i = 5√2 sin(ωt − 60°) A. Find the average power absorbed by the load.

G1 Physics · Accepted Answer

Here Vᵣₘₛ = 100 V, Iᵣₘₛ = 5 A and the phase difference is 60°. Therefore, Pₐᵥg = VᵣₘₛIᵣₘₛcos60° = 100 × 5 × 1/2 = 250 W.